Python: Delete a specific row from a given SQLite table
Python SQLite Database: Exercise-11 with Solution
Write a Python program to delete a specific row from a given SQLite table.
Sample Solution:
Python Code :
import sqlite3
from sqlite3 import Error
def sql_connection():
try:
conn = sqlite3.connect('mydatabase.db')
return conn
except Error:
print(Error)
def sql_table(conn):
cursorObj = conn.cursor()
# Create the table
cursorObj.execute("CREATE TABLE salesman(salesman_id n(5), name char(30), city char(35), commission decimal(7,2));")
# Insert records
cursorObj.executescript("""
INSERT INTO salesman VALUES(5001,'James Hoog', 'New York', 0.15);
INSERT INTO salesman VALUES(5002,'Nail Knite', 'Paris', 0.25);
INSERT INTO salesman VALUES(5003,'Pit Alex', 'London', 0.15);
INSERT INTO salesman VALUES(5004,'Mc Lyon', 'Paris', 0.35);
INSERT INTO salesman VALUES(5005,'Paul Adam', 'Rome', 0.45);
""")
cursorObj.execute("SELECT * FROM salesman")
rows = cursorObj.fetchall()
print("Agent details:")
for row in rows:
print(row)
print("\nDelete Salesman of ID 5003:")
s_id = 5003
cursorObj.execute("""
DELETE FROM salesman
WHERE salesman_id = ?
""", (s_id,))
conn.commit()
cursorObj.execute("SELECT * FROM salesman")
rows = cursorObj.fetchall()
print("\nAfter updating Agent details:")
for row in rows:
print(row)
sqllite_conn = sql_connection()
sql_table(sqllite_conn)
if (sqllite_conn):
sqllite_conn.close()
print("\nThe SQLite connection is closed.")
Sample Output:
Agent details: (5001, 'James Hoog', 'New York', 0.15) (5002, 'Nail Knite', 'Paris', 0.25) (5003, 'Pit Alex', 'London', 0.15) (5004, 'Mc Lyon', 'Paris', 0.35) (5005, 'Paul Adam', 'Rome', 0.45) Delete Salesman of ID 5003: After updating Agent details: (5001, 'James Hoog', 'New York', 0.15) (5002, 'Nail Knite', 'Paris', 0.25) (5004, 'Mc Lyon', 'Paris', 0.35) (5005, 'Paul Adam', 'Rome', 0.45) The SQLite connection is closed.
Python Code Editor:
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Previous: Write a Python program to update all the values of a specific column of a given SQLite table.
Next: Write a Python program to alter a given SQLite table.
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Python: Tips of the Day
Creates a dictionary with the same keys as the provided dictionary and values generated by running the provided function for each value:
Example:
def tips_map_values(obj, fn): ret = {} for key in obj.keys(): ret[key] = fn(obj[key]) return ret users = { 'Owen': { 'user': 'Owen', 'age': 29 }, 'Eddie': { 'user': 'Eddie', 'age': 15 } } print(tips_map_values(users, lambda u : u['age'])) # {'Owen': 29, 'Eddie': 15}
Output:
{'Owen': 29, 'Eddie': 15}
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