Python: Update all the values of a specific column of a given SQLite table

Python SQLite Database: Exercise-10 with Solution

Write a Python program to update all the values of a specific column of a given SQLite table.

Sample Solution:

Python Code :

import sqlite3 
from sqlite3 import Error 
def sql_connection():
    try:
      conn = sqlite3.connect('mydatabase.db')
      return conn
    except Error:
      print(Error) 
def sql_table(conn):
    cursorObj = conn.cursor()
# Create the table
    cursorObj.execute("CREATE TABLE salesman(salesman_id n(5), name char(30), city char(35), commission decimal(7,2));")
# Insert records
    cursorObj.executescript("""
    INSERT INTO salesman VALUES(5001,'James Hoog', 'New York', 0.15);
    INSERT INTO salesman VALUES(5002,'Nail Knite', 'Paris', 0.25);
    INSERT INTO salesman VALUES(5003,'Pit Alex', 'London', 0.15);
    INSERT INTO salesman VALUES(5004,'Mc Lyon', 'Paris', 0.35);
    INSERT INTO salesman VALUES(5005,'Paul Adam', 'Rome', 0.45);
    """)    
    cursorObj.execute("SELECT * FROM salesman")
    rows = cursorObj.fetchall()
    print("Agent details:")
    for row in rows:
        print(row)
    print("\nUpdate all commision to .55:")
    sql_update_query = """Update salesman set commission = .55"""
    cursorObj.execute(sql_update_query)
    conn.commit()
    print("Record Updated successfully ")    
    cursorObj.execute("SELECT * FROM salesman")
    rows = cursorObj.fetchall()
    print("\nAfter updating Agent details:")
    for row in rows:
        print(row)
sqllite_conn = sql_connection()
sql_table(sqllite_conn)
if (sqllite_conn):
  sqllite_conn.close()
  print("\nThe SQLite connection is closed.")

Sample Output:

Agent details:
(5001, 'James Hoog', 'New York', 0.15)
(5002, 'Nail Knite', 'Paris', 0.25)
(5003, 'Pit Alex', 'London', 0.15)
(5004, 'Mc Lyon', 'Paris', 0.35)
(5005, 'Paul Adam', 'Rome', 0.45)

Update all commision to .55:
Record Updated successfully 

After updating Agent details:
(5001, 'James Hoog', 'New York', 0.55)
(5002, 'Nail Knite', 'Paris', 0.55)
(5003, 'Pit Alex', 'London', 0.55)
(5004, 'Mc Lyon', 'Paris', 0.55)
(5005, 'Paul Adam', 'Rome', 0.55)

The SQLite connection is closed.

Python Code Editor:

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