Python: Alter a given SQLite table
Python SQLite Database: Exercise-12 with Solution
Write a Python program to alter a given SQLite table.
Sample Solution:
Python Code :
import sqlite3
from sqlite3 import Error
def sql_connection():
try:
conn = sqlite3.connect('mydatabase.db')
return conn
except Error:
print(Error)
def sql_table(conn):
cursorObj = conn.cursor()
cursorObj.execute("CREATE TABLE agent_master(agent_code char(6),agent_name char(40),working_area char(35),commission decimal(10,2),phone_no char(15) NULL);")
print("\nagent_master file has created.")
# adding a new column in the agent_master table
cursorObj.execute("""
ALTER TABLE agent_master
ADD COLUMN FLAG BOOLEAN;
""")
print("\nagent_master file altered.")
conn.commit()
sqllite_conn = sql_connection()
sql_table(sqllite_conn)
if (sqllite_conn):
sqllite_conn.close()
print("\nThe SQLite connection is closed.")
Sample Output:
agent_master file has created. agent_master file altered. The SQLite connection is closed.
Python Code Editor:
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Previous: Write a Python program to delete a specific row from a given SQLite table.
Next: Write a Python program to create a backup of a SQLite database.
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Python: Tips of the Day
Creates a dictionary with the same keys as the provided dictionary and values generated by running the provided function for each value:
Example:
def tips_map_values(obj, fn): ret = {} for key in obj.keys(): ret[key] = fn(obj[key]) return ret users = { 'Owen': { 'user': 'Owen', 'age': 29 }, 'Eddie': { 'user': 'Eddie', 'age': 15 } } print(tips_map_values(users, lambda u : u['age'])) # {'Owen': 29, 'Eddie': 15}
Output:
{'Owen': 29, 'Eddie': 15}
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