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Python: Next bigger number by rearranging the digits of a given number

Python Lambda: Exercise-25 with Solution

Write a Python program to create the next bigger number by rearranging the digits of a given number.

Sample Solution:

Python Code :

def rearrange_bigger(n):
    #Break the number into digits and store in a list
    nums = list(str(n))
    for i in range(len(nums)-2,-1,-1):
        if nums[i] < nums[i+1]:
            z = nums[i:]
            y = min(filter(lambda x: x > z[0], z))
            z.remove(y)
            z.sort()
            nums[i:] = [y] + z
            return int("".join(nums))
    return False
n = 12
print("Original number:",n)
print("Next bigger number:",rearrange_bigger(n))

n = 10
print("\nOriginal number:",n)
print("Next bigger number:",rearrange_bigger(n))
      
n = 201
print("\nOriginal number:",n)
print("Next bigger number:",rearrange_bigger(n))
n = 102
print("\nOriginal number:",n)
print("Next bigger number:",rearrange_bigger(n))
n = 445
print("\nOriginal number:",n)
print("Next bigger number:",rearrange_bigger(n))

Sample Output:

Original number: 12
Next bigger number: 21

Original number: 10
Next bigger number: False

Original number: 201
Next bigger number: 210

Original number: 102
Next bigger number: 120

Original number: 445
Next bigger number: 454

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Previous: Write a Python program to find numbers within a given range where every number is divisible by every digit it contains.
Next: Write a Python program to find the list with maximum and minimum length using lambda.

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Python: Tips of the Day

Creates a dictionary with the same keys as the provided dictionary and values generated by running the provided function for each value:

Example:

def tips_map_values(obj, fn):
  ret = {}
  for key in obj.keys():
    ret[key] = fn(obj[key])
  return ret
users = {
  'Owen': { 'user': 'Owen', 'age': 29 },
  'Eddie': { 'user': 'Eddie', 'age': 15 }
}

print(tips_map_values(users, lambda u : u['age'])) # {'Owen': 29, 'Eddie': 15}

Output:

{'Owen': 29, 'Eddie': 15}