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Python: Find numbers within a given range where every number is divisible by every digit it contains

Python Lambda: Exercise-24 with Solution

Write a Python program to find numbers within a given range where every number is divisible by every digit it contains.

Sample Solution:

Python Code :

def divisible_by_digits(start_num, end_num):
    return [n for n in range(start_num, end_num+1) \
                if not any(map(lambda x: int(x) == 0 or n%int(x) != 0, str(n)))]
print(divisible_by_digits(1,22))

Sample Output:

[1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 15, 22]

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Python: Tips of the Day

Creates a dictionary with the same keys as the provided dictionary and values generated by running the provided function for each value:

Example:

def tips_map_values(obj, fn):
  ret = {}
  for key in obj.keys():
    ret[key] = fn(obj[key])
  return ret
users = {
  'Owen': { 'user': 'Owen', 'age': 29 },
  'Eddie': { 'user': 'Eddie', 'age': 15 }
}

print(tips_map_values(users, lambda u : u['age'])) # {'Owen': 29, 'Eddie': 15}

Output:

{'Owen': 29, 'Eddie': 15}