w3resource

Python: Find the list with maximum and minimum length using lambda

Python Lambda: Exercise-26 with Solution

Write a Python program to find the list with maximum and minimum length using lambda.

Sample Solution:

Python Code :

def max_length_list(input_list):
    max_length = max(len(x) for x in input_list )   
    max_list = max(input_list, key = lambda i: len(i))    
    return(max_length, max_list)
    
def min_length_list(input_list):
    min_length = min(len(x) for x in input_list )  
    min_list = min(input_list, key = lambda i: len(i))
    return(min_length, min_list)
      
list1 = [[0], [1, 3], [5, 7], [9, 11], [13, 15, 17]]
print("Original list:")
print(list1)
print("\nList with maximum length of lists:")
print(max_length_list(list1))
print("\nList with minimum length of lists:")
print(min_length_list(list1))

Sample Output:

Original list:
[[0], [1, 3], [5, 7], [9, 11], [13, 15, 17]]

List with maximum length of lists:
(3, [13, 15, 17])

List with minimum length of lists:
(1, [0])

Visualize Python code execution:

The following tool visualize what the computer is doing step-by-step as it executes the said program:


Python Code Editor:

Have another way to solve this solution? Contribute your code (and comments) through Disqus.

Previous: Write a Python program to create the next bigger number by rearranging the digits of a given number.
Next: Write a Python program to sort each sublist of strings in a given list of lists using lambda.

What is the difficulty level of this exercise?

Test your Python skills with w3resource's quiz


Python: Tips of the Day

Inverts a dictionary with non-unique hashable values:

Example:

def tips_collect_dictionary(obj):
  inv_obj = {}
  for key, value in obj.items():
    inv_obj.setdefault(value, list()).append(key)
  return inv_obj
ages = {
  "Owen": 25,
  "Jhon": 25,
  "Pepe": 15,
}
print(tips_collect_dictionary(ages))

Output:

{25: ['Owen', 'Jhon'], 15: ['Pepe']}