Scala Programming: Find smallest and second smallest elements of a given array
Scala Programming Array Exercise-27 with Solution
Write a Scala program to find smallest and second smallest elements of a given array.
Sample Solution:
Scala Code:
object Scala_Array {
def main(args: Array[String]): Unit = {
val arr = Array(5, 6, -9, 6, 15, 4);
println("Original array:")
for (x <- arr) {
print(s"${x}, ")
}
var first_element, second_element, arr_size = arr.length;
/* Return if the array size less than two */
if (arr_size < 2) {
println("\nArray size less than two.");
} else {
first_element = Int.MaxValue
second_element = Int.MaxValue
for (i <- 0 to arr_size - 1) {
/* Update both first and second if current element is smaller than first. */
if (arr(i) < first_element) {
second_element = first_element;
first_element = arr(i);
}
/* Update second if arr[i] is between first and second
elements.*/
else if (arr(i) < second_element && arr(i) != first_element)
second_element = arr(i);
}
if (second_element == Integer.MAX_VALUE)
println("\nNo second smallest element.");
else
println(
s"\nThe smallest element is ${first_element} and second Smallest element is ${second_element}."
);
}
}
}
Sample Output:
Original array: 5, 6, -9, 6, 15, 4, The smallest element is -9 and second Smallest element is 4.
Scala Code Editor :
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Previous: Write a Scala program to remove the duplicate elements of a given sorted array and return the new length of the array.
Next: Write a Scala program to segregate all 0s on left side and all 1s on right side of a given array of 0s and 1s.
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