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Python: Create a SQLite database and connect with the database and print the version of the SQLite database

Python SQLite Database: Exercise-1 with Solution

Write a Python program to create a SQLite database and connect with the database and print the version of the SQLite database.

Sample Solution:

Python Code :

import sqlite3
try:
   sqlite_Connection = sqlite3.connect('temp.db')
   conn = sqlite_Connection.cursor()
   print("\nDatabase created and connected to SQLite.")
   sqlite_select_Query ="select sqlite_version();"
   conn.execute(sqlite_select_Query)
   record = conn.fetchall()
   print("\nSQLite Database Version is: ", record)
   conn.close()
except sqlite3.Error as error:
   print("\nError while connecting to sqlite", error)
finally:
   if (sqlite_Connection):
       sqlite_Connection.close()
       print("\nThe SQLite connection is closed.")

Sample Output:

Database created and connected to SQLite.

SQLite Database Version is:  [('3.11.0',)]

The SQLite connection is closed.

Alternate solution (Connect to a SQLite Database):

Python Code :

import  sqlite3
print("creating connecting ...")
conn  =  sqlite3.connect ('mydatabase.db' )
conn . close ()
print("\nThe SQLite connection is closed.")

Sample Output:

creating connecting ...

The SQLite connection is closed.

Python Code Editor:

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Python: Tips of the Day

Creates a dictionary with the same keys as the provided dictionary and values generated by running the provided function for each value:

Example:

def tips_map_values(obj, fn):
  ret = {}
  for key in obj.keys():
    ret[key] = fn(obj[key])
  return ret
users = {
  'Owen': { 'user': 'Owen', 'age': 29 },
  'Eddie': { 'user': 'Eddie', 'age': 15 }
}

print(tips_map_values(users, lambda u : u['age'])) # {'Owen': 29, 'Eddie': 15}

Output:

{'Owen': 29, 'Eddie': 15}