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Python: Sort a list of dictionaries using Lambda

Python Lambda: Exercise-4 with Solution

Write a Python program to sort a list of dictionaries using Lambda.

Sample Solution:

Python Code :

models = [{'make':'Nokia', 'model':216, 'color':'Black'}, {'make':'Mi Max', 'model':'2', 'color':'Gold'}, {'make':'Samsung', 'model': 7, 'color':'Blue'}]
print("Original list of dictionaries :")
print(models)
sorted_models = sorted(models, key = lambda x: x['color'])
print("\nSorting the List of dictionaries :")
print(sorted_models)

Sample Output:

Original list of dictionaries :
[{'make': 'Nokia', 'model': 216, 'color': 'Black'}, {'make': 'Mi Max', 'model': '2', 'color': 'Gold'}, {'make': 'Samsung', 'model': 7, 'color': 'Blue'}]

Sorting the List of dictionaries :
[{'make': 'Nokia', 'model': 216, 'color': 'Black'}, {'make': 'Samsung', 'model': 7, 'color': 'Blue'}, {'make': 'Mi Max', 'model': '2', 'color': 'Gold'}]

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Python: Tips of the Day

Creates a dictionary with the same keys as the provided dictionary and values generated by running the provided function for each value:

Example:

def tips_map_values(obj, fn):
  ret = {}
  for key in obj.keys():
    ret[key] = fn(obj[key])
  return ret
users = {
  'Owen': { 'user': 'Owen', 'age': 29 },
  'Eddie': { 'user': 'Eddie', 'age': 15 }
}

print(tips_map_values(users, lambda u : u['age'])) # {'Owen': 29, 'Eddie': 15}

Output:

{'Owen': 29, 'Eddie': 15}