Python Linked List: Access a specific item in a singly linked list using index value
Python Linked List: Exercise-4 with Solution
Write a Python program to access a specific item in a singly linked list using index value.
Sample Solution:-
Python Code:
class Node:
# Singly linked node
def __init__(self, data=None):
self.data = data
self.next = None
class singly_linked_list:
def __init__(self):
# Createe an empty list
self.tail = None
self.head = None
self.count = 0
def append_item(self, data):
#Append items on the list
node = Node(data)
if self.head:
self.head.next = node
self.head = node
else:
self.tail = node
self.head = node
self.count += 1
def __getitem__(self, index):
if index > self.count - 1:
return "Index out of range"
current_val = self.tail
for n in range(index):
current_val = current_val.next
return current_val.data
items = singly_linked_list()
items.append_item('PHP')
items.append_item('Python')
items.append_item('C#')
items.append_item('C++')
items.append_item('Java')
print("Search using index:")
print(items[0])
print(items[1])
print(items[4])
print(items[5])
print(items[10])
Sample Output:
Search using index: PHP Python Java Index out of range Index out of range
Flowchart:
Python Code Editor:
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Previous: Write a Python program to search a specific item in a singly linked list and return true if the item is found otherwise return false.
Next: Write a Python program to set a new value of an item in a singly linked list using index value.
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Python: Tips of the Day
Creates a dictionary with the same keys as the provided dictionary and values generated by running the provided function for each value:
Example:
def tips_map_values(obj, fn): ret = {} for key in obj.keys(): ret[key] = fn(obj[key]) return ret users = { 'Owen': { 'user': 'Owen', 'age': 29 }, 'Eddie': { 'user': 'Eddie', 'age': 15 } } print(tips_map_values(users, lambda u : u['age'])) # {'Owen': 29, 'Eddie': 15}
Output:
{'Owen': 29, 'Eddie': 15}
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