Java programming Exercises: Set thousands separator in the said number
Java Regular Expression: Exercise-20 with Solution
Write a Java program that takes a number and set thousands separator in that number.
Sample Solution:
Java Code:
import java.text.NumberFormat;
import java.util.Locale;
import java.text.Format;
public class test {
public static void main(String[] args) {
int n = 100;
System.out.println("Original Number: "+n);
System.out.println("Set thousands separator in the said number): "+validate(n));
n = 1000;
System.out.println("\nOriginal Number: "+n);
System.out.println("Set thousands separator in the said number): "+validate(n));
n = 10000;
System.out.println("\nOriginal Number: "+n);
System.out.println("Set thousands separator in the said number): "+validate(n));
n = 100000;
System.out.println("\nOriginal Number: "+n);
System.out.println("Set thousands separator in the said number): "+validate(n));
n = 1000000;
System.out.println("\nOriginal Number: "+n);
System.out.println("Set thousands separator in the said number): "+validate(n));
}
public static String validate(int n) {
String num = Integer.toString(n);
int len = num.length();
if(len < 4) {
return num;
}
//You can use any character as separator
return validate(Integer.parseInt(num.substring(0, len-3))) + '#' + num.substring(len-3);
}
}
Sample Output:
Original Number: 100 Set thousands separator in the said number): 100 Original Number: 1000 Set thousands separator in the said number): 1#000 Original Number: 10000 Set thousands separator in the said number): 10#000 Original Number: 100000 Set thousands separator in the said number): 100#000 Original Number: 1000000 Set thousands separator in the said number): 1#000#000
Pictorial Presentation:
Flowchart :
Java Code Editor:
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Java: Tips of the Day
What is the best way to filter a Java Collection?
Java 8 (2014) solves this problem using streams and lambdas in one line of code:
List<Person> beerDrinkers = persons.stream() .filter(p -> p.getAge() > 16).collect(Collectors.toList());
Use Collection#removeIf to modify the collection in place. (Notice: In this case, the predicate will remove objects who satisfy the predicate):
persons.removeIf(p -> p.getAge() <= 16);
lambdaj allows filtering collections without writing loops or inner classes:
ListbeerDrinkers = select(persons, having(on(Person.class).getAge(), greaterThan(16)));
Ref: https://bit.ly/3uwYid6
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