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Java programming Exercises: Check for a number at the end of a string

Java Regular Expression: Exercise-11 with Solution

Write a Java program to check for a number at the end of a given string.

Sample Solution:

Java Code:

import java.util.*;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class test {
 
   public static void main(String[] args) {
	   
	    System.out.println(validate("abcdef"));
		System.out.println(validate("3abcdef"));
        System.out.println(validate("abcdef9"));
		System.out.println(validate("abcdef3459"));
        }

   public static String validate(String text) {
	    Pattern pattern = Pattern.compile(".*[0-9]$");
		Matcher m = pattern.matcher(text);
		
	    if (m.find())
            return "Found a match!";
        else
            return "Not matched!";
   }
}

Sample Output: 

Not matched!
Not matched!
Found a match!
Found a match!

Pictorial Presentation:

Java Regular Expression: Check for a number at the end of a string.

Flowchart :

Flowchart: Check for a number at the end of a string.

Java Code Editor:

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Java: Tips of the Day

What is the best way to filter a Java Collection?

Java 8 (2014) solves this problem using streams and lambdas in one line of code:

List<Person> beerDrinkers = persons.stream()
    .filter(p -> p.getAge() > 16).collect(Collectors.toList());

Use Collection#removeIf to modify the collection in place. (Notice: In this case, the predicate will remove objects who satisfy the predicate):

persons.removeIf(p -> p.getAge() <= 16);

lambdaj allows filtering collections without writing loops or inner classes:

List beerDrinkers = select(persons, having(on(Person.class).getAge(),
    greaterThan(16)));

Ref: https://bit.ly/3uwYid6